Percent problems

Google Classroom

Problem

A brand of cereal had $1.2$1, point, 2 milligrams $(\text{mg})$left parenthesis, start text, m, g, end text, right parenthesis of iron per serving. Then they changed their recipe so they had $1.8\,\text{mg}$1, point, 8, start text, m, g, end text of iron per serving.

What was the percent increase in iron?

 $\%$percent

Hint #11 / 5

Let's start by finding the amount of increase in iron.

$1.8\,\text{mg}-1.2\,\text{mg}=0.6\,\text{mg}$1, point, 8, start text, m, g, end text, minus, 1, point, 2, start text, m, g, end text, equals, 0, point, 6, start text, m, g, end text

What percent of $1.2$1, point, 2 milligrams is $0.6$0, point, 6 milligrams?

Hint #22 / 5

We can rewrite that question as an equation.

$\begin{array}{ccccc} \blueD{\text{what percent}}&\text{of}&\greenD{1.2\,\text{mg}}&\text{is}&0.6\,\text{mg}\\\\ \blueD{?\%}&\times &\greenD{1.2}&=&0.6 \end{array}$

Hint #33 / 5

Let's solve for the percent.

$\begin{aligned} \dfrac{\blueD{?\%}\times \greenD{1.2}}{1.2}&=\dfrac{0.6}{1.2}\\\\ \blueD{?\%}&=\blueD{0.5} \end{aligned}$

Hint #44 / 5

Percent means per hundred, so $\blueD{0.5}$start color #11accd, 0, point, 5, end color #11accd is equivalent to $\blueD{\dfrac{50}{100}}$start color #11accd, start fraction, 50, divided by, 100, end fraction, end color #11accd and also to $\blueD{50\%}$start color #11accd, 50, percent, end color #11accd.

Hint #55 / 5

There was a $50\%$50, percent increase in iron.